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Q: How do you factor y2 plus 14y plus 49?

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This is not factor-able.

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(y - 5)(y - 6)

y (y - 6) (y - 8)y3 -14y2 +48y=y (y2 - 14y + 48)= y (y - 6) (y - 8)

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I feel like there is something wrong with your question because subtracting y2 on both sides leaves you with 8y=0; then, y=0

It goes to (x-5)(x-3)

(y + 8)(y - 2)

y2 + y2 = 2y2

It is: y2