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NORMALLY DISTRIBUTED DATA # # lower-tail test, minimum detectable difference # > summary(normal.sample.size(mean = 100, sd1 = 10, n1 = (1:5)*20, power = .9, alt = "l")) mean.alt delta power n1 1 93.45636 -6.543641 0.9 20 2 95.37295 -4.627053 0.9 40 3 96.22203 -3.777973 0.9 60 4 96.72818 -3.271821 0.9 80 5 97.07359 -2.926405 0.9 100 See the online help files for for more details. normal.sample.size and summary.power.table Comparing Means From Two Samples Extending this formula to two-sampled tests, is relatively easy. Given two independent samples from normal distributions X1, i ∼ N ( µ 1, σ 12 ) i = 1, …, n 1 X2, j ∼ N ( µ2, σ 22 ) j = 1, …, n 2 where n 2 = kn 1 , we'll construct a two-sided test of equality of means H o : µ1 = µ 2 H a : µ1 ≠ µ 2 which is more conveniently written H o : µ 2 – µ1 = 0 Ha : µ2 – µ1 ≠ 0 143