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Important Information 30000 25000 20000 15 15000 20 10000 25 5000 4000 30 Exemple: Beispiel: JJ 2 == 15'000 15'000kgcm kgcm2 == 120° 120° p bar p == 55bar 3000 35 Results: Resultate: 2000 nmax = 20 min.-1-1 1500 tt 1000 Fig. 3 = 180° = 150° = 60° = 90° = 120° n [1/min] J [kgcm2] Performance diagram * nmax = 20 min. = 0.74 = 0,74ss 40 t [s] 500 400 p = 2 bar p = 3 bar p = 4 bar p = 5 bar p = 6 bar 2,0 1,5 1,0 0,5 0,4 0,3 0,2 0,1 J = Massenträgheitsmoment Anzahl of Doppelhübe Jn == max. Mass moment inertia p = pneum. Antriebsdruck n = Max. number double strokes t = Verfahrzeit pro Hub p = Pneumatic op. pressure = Drehwinkel t = Travel time per stroke = Angle of rotation * Scope: – Centre of gravity of the rotating mass located on the axis of rotation, which may be in any position. – Centre of gravity of the rotating mass off set from the axis of rotation, with the axis vertical. 4