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Figure 3 - Flexible Joint - Stationary Figure 4 - Flexible Joint - Moving Figure 3 above depicts the joint at rest while Figure 4 depicts the joint at a given α. Notice that spring #1 has been compressed and spring #2 has been stretched (with respect to the joint's stationary state). We shall begin by deriving the lengths of each spring in Figure 4. L 1x =r−Rsin L 1y =Rcos −d L 2x =rRsin L 2y =L 1y =Rcos −d L 1= L 21x L 21y 2 [3.1] 2 L 2= L 2x L 2y Next we will derive the force acting on each spring: F 1=K L 1−LF r F 2=K L 2−L F r L L F 1x =F 1 1x , F 1y =F 1 1y L1 L1 L L F 2x =F 2 2x , F 2y =F 2 2y L2 L2 [3.2] * Fr is the restoring force on each spring. The springs supplied come pre-loaded meaning they will not stretch before the force Fr is applied. Page # 4 Revision: 01