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Transcript
Canonical Forms The block diagrams for h(z)/e(z) follow. e(z) + h(z) z -1 z -1 z -1 -a1 -a2 -an h(z) 1 ----------- = ------------------------------------------------------------------------------–1 –2 –n e(z) 1 + a 1 z + a 2 z + ... + a n z Combining these two block diagrams yields the direct form II diagram shown below. Notice that the feedforward part (top of block diagram) contains the numerator coefficients and the feedback part (bottom of block diagram) contains the denominator coefficients. b0 b1 bm + e(z) + h(z) z -1 z -1 z -1 z u(z) u ( z )---------e(z) -1 -a1 -a2 -am -an 5-9
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