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OPN/51/1.5.3 Page 166 of 232 User Manual Issue 2014-11-05 In the diagram above we can see the auxiliary power of the trailers is 30kW and on top of this are the 100 kW of the engine. This is in total 130 kW for course ABCs_02. P_aux = f(t) 132 131 P [kW] 130 129 128 127 126 00 02:00:00 00 02:10:00 00 02:20:00 00 02:30:00 Sim: 26; Course: ABCs_02; Engine: 0-Engine1 00 02:40:00 00 02:50:00 Sim: 27; Course: ABCs_02; Engine: 0-Engine1 Figure 164 The auxiliary power of course ABCs_02 with constant engine auxiliary power (sim 26) and constant auxiliary resistance (sim 27). In Figure 164 we see the constant power and constant resistance auxiliary have about the same values. But of course the constant resistance auxiliary has the auxiliary power as a function of the pantograph voltage, compare to the pantograph voltage in Figure 165. U = f(t) 27700 27600 27500 27400 U [V] 27300 27200 27100 27000 26900 26800 00 02:00:00 00 02:10:00 00 02:20:00 Sim: 26; Course: ABCs_02; Engine: 0-Engine1 00 02:30:00 00 02:40:00 00 02:50:00 Sim: 27; Course: ABCs_02; Engine: 0-Engine1 Figure 165 The pantograph voltage of course ABCs_02 with constant engine auxiliary power (sim 26) and constant auxiliary resistance (sim 27). IFB DD, UM_OPN_51_01.05.03.docx Page 166 of 232 DMJ, 2014-11-05
